正则表达式查找给定范围内5个连续数字的一个或多个实例

Question

I am a newbie at RegEx, so I need some help. Can anyone help me parse a string and find one or more instances of numbers that range from 40000 to 99999 ? Here are some example strings:

• Order Details, Acme, #46405,53000,86232, for 4/17 - 3 instances
• PSA Order Detail: Hiring Practices (46445); starting 4-16-12 - 1 instance
• PC Pitstop 32134 Direct for 4/18/12 - 0 instances

Answer 1

You could try something like this:

(?<!\d)[4-9]\d{4}(?!\d)

See it on regexr

EDIT: here is a c# code snippet to test it:

// could be whatever
var str = "50000 alpha 43 84100";
var regex = new Regex(@"(?<!\d)[4-9]\d{4}(?!\d)");
foreach (Match match in regex.Matches(str))
    Console.WriteLine(match.Value);

this outputs:

50000
84100

Answer 2

You should use regex

(?<!\d)([4-9]\d{4})(?!\d)

---

Untested code:

using System;
using System.Collections;
using System.Text.RegularExpressions;

class Program
{
  static void Main()
  {
    string input = "50000 Order Acme, #46405,53000,86232, for 4/17 60000";
    Regex t = new Regex(@"(?<!\d)([4-9]\d{4})(?!\d)", RegexOptions.Singleline) 
    MatchCollection theMatches = t.Matches(input) 
    for (int counter = 0; counter < theMatches.Count; counter++)
    {
      Console.WriteLine(theMatches[counter].Value); 
    }
  }
}

For multi-line input use RegexOptions.Multiline instead of RegexOptions.Singleline .

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Note: I suggest you always test regex with match at the begining and end of string.