如何拆分Java字符串但保留其部分内容？

Question

I am working on java string split. I wish to split the String according to ". uppercase"(There is a space between " . " and "uppercase"), for example:

". A" ". B" ". C"...

Also, I wish to preserve the "." and the "uppercase", is there any efficient way to do that? I use

String.split("\\.\\s") 

before, but it will remove the "." I use. So that's not an ideal solution. Thanks

Sample result

String = This is an Egg. This is a dog. "I just come up with this example"
String[0] = This is an Egg.
String[1] = This is a dog. "I just come up with this example"

More edit:

There is an issue that the usual way seems will preserve the delimiter at one of it's string. but I wish to split the delimiter in some sense.(in my example, the ". [AZ]" is splited too)

Answer 1

You can use a lookaround :

str.split("(?<=\\.\\s+)(?=\p{Lu})")

This will split "First sentence. Foo bar. test" into the array

{ "First sentence. ", 
  "Foo bar. test" }

If you don't want the space to be included, just put it between the lookaround assertions:

str.split("(?<=\\.)\\s+(?=\p{Lu}")

This will result in

{ "First sentence.", 
  "Foo bar. test" }

For the example string above.

Answer 2

Here You go:

Use str.replaceAll(". ",".##");

str.replaceAll(".",".##");

Then use String.split("##")

This will give you the required string.

Check this link