[英]Generating a jar with the source code of the Maven project with the Maven directory structure?
I have a web application that I build with Maven into a war. 我有一个Web应用程序,我用Maven构建了一个战争。 But I want to generate a JAR with the maven project with the correct maven directory structure. 但是我希望使用具有正确maven目录结构的maven项目生成JAR。 I tried this but it throws away the Maven directory structure (src/main/java, etc.). 我尝试了这个,但它抛弃了Maven目录结构(src / main / java等)。 My goal is to distribute this jar to other people so they can unpack and run mvn eclipse:eclipse and start working on their new web project. 我的目标是将这个jar分发给其他人,这样他们就可以解压缩并运行mvn eclipse:eclipse并开始处理他们的新Web项目。
Why not using the existing descriptor of maven-assembly-plugin .. 为什么不使用maven-assembly-plugin的现有描述符..
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.3</version>
<configuration>
<descriptorRefs>
<descriptorRef>src</descriptorRef>
</descriptorRefs>
</configuratio
Use the maven-assembly-plugin. 使用maven-assembly-plugin。 It's pretty straight-forward to do what you want. 做你想做的事情非常简单。
Here's your definition for the plugin: 这是你对插件的定义:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2.1</version>
<executions>
<execution>
<id>make-distribution</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
<configuration>
<descriptors>
<descriptor>src/main/assembly/assembly.xml</descriptor>
</descriptors>
</configuration>
</execution>
</executions>
</plugin>
Here's your src/main/assembly/assembly.xml: 这是你的src / main / assembly / assembly.xml:
<assembly>
<id>my-project</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>true</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${basedir}</directory>
<includes>
<include>**/**</include>
</includes>
<excludes>
<exclude>**/**</exclude>
</excludes>
</fileSet>
</fileSets>
</assembly>
I haven't tested it, but it's roughly the way you should set it up. 我没有测试过它,但它大致就是你应该设置它的方式。
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