[英]Count num_rows base on field value
*The actual problem is quite more complex than the post title :S *实际问题比帖子标题复杂得多:S
Suppose I have table 假设我有桌子
ID | vote_id | vote_type | vote_user
1 ---- 2 ----- up ------- Tom
2 ---- 3 ----- up ------- John
3 ---- 3 ----- down ----- Harry
4 ---- 4 ----- up ------- Tom
5 ---- 2 ----- down ----- John
6 ---- 3 ----- down ----- Tom
So what I want to do is 所以我想做的是
And the way I do is. 我的方法是
$up=0;
$down=0;
$voted="no";
$r=mysql_query("SELECT*FROM table_name WHERE vote_id == 3");
while($row=mysql_fetch_array($r){
if($row["vote_type"]=="up"){ $up++;}else{$down++;}
if($row["vote_user"=="John"){ $voted="yes";}
}
But is there a way ( equivalent code ) to do this without using WHILE LOOP because the actual table can be very large so running while loop can be very exhaustive :S 但是有一种方法(等效代码)无需使用WHILE LOOP即可执行此操作,因为实际表可能非常大,因此运行while循环可能非常详尽:
EDIT Can I do with single query? 编辑我可以使用单个查询吗?
Use two separate queries: 使用两个单独的查询:
Count all votes : 计算所有票数 :
SELECT vote_type, COUNT(*) AS amount
FROM table_name
WHERE vote_id = 3
GROUP BY vote_type
will return up to two rows: 最多返回两行:
vote_type | amount
----------+--------
up | 1
down | 2
Find out if John voted : 找出约翰是否投票 :
SELECT vote_type
FROM table_name
WHERE vote_id = 3
AND vote_user = 'John'
will return a row containing either up
, down
or NULL
based on how John voted. 将根据John的投票方式返回包含
up
, down
或NULL
的行。 Assuming he can only vote once... 假设他只能投票一次...
Note that adding indexes on vote_type
and maybe vote_user
will help performance. 请注意,在
vote_type
或也许vote_user
上添加索引将有助于提高性能。
You can run this query to give you a table of votes up and down for a specific vote_id. 您可以运行此查询为您提供特定表决_id的上下表决表。
select vote_type, COUNT(*) from votes where vote_id = 2 AND group by vote_type
I would run another query to check to see if John voted for that vote_id or not 我将运行另一个查询来检查约翰是否投票给了vote_id
select count(*) from votes where vote_id = 2 AND vote_user = 'John'
In a single query 在一个查询中
Select
sum(case when vote_type = 'up' then 1 else 0 end) as up,
sum(case when vote_type = 'down' then 1 else 0 end) as down,
sum(case when vote_user = 'john' then 1 else 0 end) as john
from
yourTable
where
vote_id = 3
Or any variation of sum(case when) 或总和的任何变化(当情况下)
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