如何在shell中使用regular-expression来grep这个模式？

Question

I want to grep the pattern like "1-10","10-20","1-9"(without double quotes) with the following code:

grep '[[:digit:]]\-[[:digit:]]' mydoc

It is ok to grep "1-9" but I can't figure out how to grep other two patterns!

Answer 1

The minus needs no masking. + allows multiple occurrences.

egrep '[0-9]+-[0-9]+' mydoc

Answer 2

grep -E '[[:digit:]]+-[[:digit:]]+' mydoc

grep -E '[[:digit:]]{1,2}-[[:digit:]]{1,2}' mydoc

？