如何选择提交不同的php页面的选项

Question

drop down select "sales" go to sales.php, other options selected go to addFund.php...

<form name='searform' method='post' action='<?php echo $home;?>addFund.php'>
Search : <input type='text' id='sear' name='sear'> by 
<select id='psel' name='psel' onchange='change()'>
<option value='email'>Email</option>
<option value='name'>Username</option>
<option value='domain'>Domain name</option>
<option value='sales'>Sales</option>
</select>
<input type='submit' name='sub' id='sub' value='Go' onclick='gopage()'>
<input type='submit' name='dir' id='dir' value='Direct'>
</form>

How to submit different pages

Answer 1

You could use some Javascript nastiness to achieve this with the change() function, but the usual way to do this is to route all requests through a controller and include() the appropriate page. For example, point your form to action.php , and in that file, do this:

action.php

<?php

  if (isset($_POST['psel']) && $_POST['psel'] == 'sales') {
    include 'sales.php';
  } else {
    include 'addFund.php';
  }

...or you could just put roughly that code into addFund.php , since you only seem to have one other script that you would want to send requests to.

Answer 2

You could do this with javascript:

function change(el) {
  if(el.value === 'sales') {
    el.form.action = 'sales.php';
  } else {
    el.form.action = 'addFund.php';
  }
}

Change the onchange to onchange="change(this)" . A better way would be to check the variable on serverside and include the right file.

Answer 3

Change your select to this:

<select name="vote" onChange="document.forms['searForm'].submit()">

And make your form action go to something like pageChange.php where it returns a different page depending on the $_POST value.