[英]Simple MySQL query and comparison
I've seen many questions like this on stack overflow, but I want to know why my code won't work. 我在堆栈溢出时已经看到很多类似的问题,但是我想知道为什么我的代码无法正常工作。 It makes perfect (logical) sense.
这是完美的(逻辑)意义。 Can anyone please explain to me what code I would have to write to actually complete the if statement I have in mind?
谁能给我解释一下我要真正完成if语句必须编写什么代码?
$result = mysql_query("SELECT confirmed FROM usernames WHERE username = '$username' AND password = '$password'")
if ($result==NULL)
echo 'Failure';
I'm attempting this in php. 我正在php中尝试。
NOTE: 注意:
confirmed in the DB is set to NULL, so the final echo should display. 在数据库中确认后将其设置为NULL,因此应显示最终回显。
The variable $result
contains an internal representation of the result of the query (as returned by the mysql_query()
function). 变量
$result
包含查询$result
的内部表示形式(由mysql_query()
函数返回)。 To get the actual value you need to use another function, like mysql_fetch_assoc()
or mysql_result()
. 为了获得实际值,您需要使用另一个函数,例如
mysql_fetch_assoc()
或mysql_result()
。 Kind of like this: 有点像这样:
$result = mysql_query("SELECT confirmed FROM usernames WHERE username = '$username' AND password = '$password'");
$conf = mysql_result($result, 0, 0);
if ($conf == NULL){
echo 'Failure';
}
You need to fetch a row! 您需要获取一行!
$row = mysql_fetch_row($result);
if($row[0] == NULL)
{
echo 'failure';
}
You can try this.... 你可以试试这个。
/*Add die for check if query has error */
/*Put Limit 0,1 for fetch only single row*/
$result = mysql_query("SELECT confirmed FROM usernames WHERE username = '$username' AND password = '$password' Limit 0,1") or die(mysql_error());
if($result){
/*check if query return result or not according sql cond*/
if(mysql_num_rows($result) == 0){
echo "No Record Found";
exit();
}
/*Assign confirmed index value to a varriable $condirmed*/
while($row = mysql_fetch_assoc($result)){
$confirmed = $row['confirmed'];
}
if($confirmed == 'NULL'){
echo "Failure";
}
}
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