[英]remove object from an array
I have an array with the following structure : 我有一个具有以下结构的数组:
var y = [{id:12,count:10}, {id:23,count:89}, {id:21,count:100},]
How can I remove element with id:23 ? 如何删除id:23的元素?
I am not willing to use to create a prototype method on the array Array.prototype.remove 我不愿意使用在数组Array.prototype.remove上创建原型方法
Any pointers appreciated 任何指针赞赏
Thanks 谢谢
ES5 code: ES5代码:
y = y.filter(function( obj ) {
return obj.id !== 23;
});
ES5 is widely supported by all major browsers. 所有主要浏览器均广泛支持ES5。 Still, you might want to include on of the several Shims to backup old'ish browsers
不过,您可能仍要包括几个Shim来备份旧式的浏览器
for (i in y) {
if (y[i].id == 23) {
y.splice(i, 1);
break;
}
}
Denis Ermolin's answer is an option, though a few problems might occur, here's what I suggest: Denis Ermolin的答案是一个选择,尽管可能会出现一些问题,但我建议这样做:
for(var i=0;i<y.length;i++)
{
if (y[i].hasOwnProperty('id') && y[i].id === 23)
{
delete(y[i]);
break;
}
}
When using arrays, it's always better to avoid the for - in
loop, as this will loop through the Array.prototype
, so i
might suddenly contain length
, not an index number. 使用数组时,最好避免
for - in
循环,因为这将遍历Array.prototype
,因此i
可能突然包含length
而不是索引号。
When you're dealing with objects, the for in
loop is a great thing, but again: it loops through the prototypes, that's why you're better off using the hasOwnProperty
method. 当您处理对象时,
for in
循环是一件很了不起的事情,但是再次:它遍历了原型,这就是为什么最好使用hasOwnProperty
方法。
The rest is pretty strait forward, I think... good luck 其余的都向前走,我想...祝你好运
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