简体   繁体   English

获取对象或类的名称

[英]Get name of object or class

Is there any solution to get the function name of an object?有没有办法获取对象的函数名?

function alertClassOrObject (o) {
   window.alert(o.objectName); //"myObj" OR "myClass" as a String
}

function myClass () {
   this.foo = function () {
       alertClassOrObject(this);
   }
}

var myObj = new myClass();
myObj.foo();

for (var k in this) {...} - there is no information about the className or ObjectName . for (var k in this) {...} - 没有关于classNameObjectName Is it possible to get one of them?是否有可能获得其中之一?

Get your object's constructor function and then inspect its name property.获取对象的构造函数,然后检查其name属性。

myObj.constructor.name

Returns "myClass".返回“myClass”。

Example:例子:

 function Foo () { console.log('Foo function'); } var f = new Foo(); console.log('f', f.constructor.name); // -> "Foo" var Bar = function () { console.log('Anonymous function (as Bar)'); }; var b = new Bar(); console.log('b', b.constructor.name); // -> "Bar" var Abc = function Xyz() { console.log('Xyz function (as Abc)'); }; var a = new Abc(); console.log('a', a.constructor.name); // -> "Xyz" class Clazz { constructor() { console.log('Clazz class'); } } var c = new Clazz(); console.log('c', c.constructor.name); // -> "Clazz" var otherClass = class Cla2 { constructor() { console.log('Cla2 class (as otherClass)'); } } var c2 = new otherClass(); console.log('c2', c2.constructor.name); // -> "Cla2"

If you use standard IIFE (for example with TypeScript)如果您使用标准 IIFE(例如使用 TypeScript)

var Zamboch;
(function (_Zamboch) {
    (function (Web) {
        (function (Common) {
            var App = (function () {
                function App() {
                }
                App.prototype.hello = function () {
                    console.log('Hello App');
                };
                return App;
            })();
            Common.App = App;
        })(Web.Common || (Web.Common = {}));
        var Common = Web.Common;
    })(_Zamboch.Web || (_Zamboch.Web = {}));
    var Web = _Zamboch.Web;
})(Zamboch || (Zamboch = {}));

you could annotate the prototypes upfront with您可以预先注释原型

setupReflection(Zamboch, 'Zamboch', 'Zamboch');

and then use _fullname and _classname fields.然后使用 _fullname 和 _classname 字段。

var app=new Zamboch.Web.Common.App();
console.log(app._fullname);

annotating function here:注释功能在这里:

function setupReflection(ns, fullname, name) {
    // I have only classes and namespaces starting with capital letter
    if (name[0] >= 'A' && name[0] <= 'Z') {
        var type = typeof ns;
        if (type == 'object') {
            ns._refmark = ns._refmark || 0;
            ns._fullname = fullname;
            var keys = Object.keys(ns);
            if (keys.length != ns._refmark) {
                // set marker to avoid recusion, just in case 
                ns._refmark = keys.length;
                for (var nested in ns) {
                    var nestedvalue = ns[nested];
                    setupReflection(nestedvalue, fullname + '.' + nested, nested);
                }
            }
        } else if (type == 'function' && ns.prototype) {
            ns._fullname = fullname;
            ns._classname = name;
            ns.prototype._fullname = fullname;
            ns.prototype._classname = name;
        }
    }
}

JsFiddle提琴手

As this was already answered, I just wanted to point out the differences in approaches on getting the constructor of an object in JavaScript.由于已经回答了这个问题,我只想指出在 JavaScript 中获取对象构造函数的方法的差异。 There is a difference between the constructor and the actual object/class name.构造函数和实际对象/类名称之间存在差异。 If the following adds to the complexity of your decision then maybe you're looking for instanceof .如果以下内容增加了您决定的复杂性,那么您可能正在寻找instanceof Or maybe you should ask yourself "Why am I doing this? Is this really what I am trying to solve?"或者也许你应该问自己“我为什么要这样做?这真的是我想要解决的问题吗?”

Notes:笔记:

The obj.constructor.name is not available on older browsers. obj.constructor.name在旧浏览器上不可用。 Matching (\\w+) should satisfy ES6 style classes.匹配(\\w+)应该满足 ES6 样式类。

Code:代码:

var what = function(obj) {
  return obj.toString().match(/ (\w+)/)[1];
};

var p;

// Normal obj with constructor.
function Entity() {}
p = new Entity();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));

// Obj with prototype overriden.
function Player() { console.warn('Player constructor called.'); }
Player.prototype = new Entity();
p = new Player();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));

// Obj with constructor property overriden.
function OtherPlayer() { console.warn('OtherPlayer constructor called.'); }
OtherPlayer.constructor = new Player();
p = new OtherPlayer();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));

// Anonymous function obj.
p = new Function("");
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));

// No constructor here.
p = {};
console.log("constructor:", what(p.constructor), "name:", p.constructor.name, "class:", what(p));

// ES6 class.
class NPC { 
  constructor() {
  }
}
p = new NPC();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));

// ES6 class extended
class Boss extends NPC {
  constructor() {
    super();
  }
}
p = new Boss();
console.log("constructor:", what(p.constructor), "name:", p.constructor.name , "class:", what(p));

Result:结果:

在此处输入图片说明

Code: https://jsbin.com/wikiji/edit?js,console代码: https : //jsbin.com/wikiji/edit?js,console

I was facing a similar difficulty and none of the solutions presented here were optimal for what I was working on.我面临着类似的困难,这里提供的解决方案都不是我正在处理的最佳解决方案。 What I had was a series of functions to display content in a modal and I was trying to refactor it under a single object definition making the functions, methods of the class.我拥有的是一系列在模式中显示内容的函数,我试图在单个对象定义下重构它,以创建类的函数和方法。 The problem came in when I found one of the methods created some nav-buttons inside the modal themselves which used an onClick to one of the functions -- now an object of the class.当我发现其中一种方法在模态本身内部创建了一些导航按钮时,问题就出现了,这些按钮使用 onClick 到其中一个函数 - 现在是类的对象。 I have considered (and am still considering) other methods to handle these nav buttons, but I was able to find the variable name for the class itself by sweeping the variables defined in the parent window.我已经考虑(并且仍在考虑)处理这些导航按钮的其他方法,但是我能够通过扫描父窗口中定义的变量来找到类本身的变量名称。 What I did was search for anything matching the 'instanceof' my class, and in case there might be more than one, I compared a specific property that was likely to be unique to each instance:我所做的是搜索与我的类的“instanceof”匹配的任何内容,如果可能有多个,我比较了每个实例可能是唯一的特定属性:

var myClass = function(varName)
{
    this.instanceName = ((varName != null) && (typeof(varName) == 'string') && (varName != '')) ? varName : null;

    /**
     * caching autosweep of window to try to find this instance's variable name
     **/
    this.getInstanceName = function() {
        if(this.instanceName == null)
        {
            for(z in window) {
                if((window[z] instanceof myClass) && (window[z].uniqueProperty === this.uniqueProperty)) {
                    this.instanceName = z;
                    break;
                }
            }
        }
        return this.instanceName;
    }
}

试试这个:

var classname = ("" + obj.constructor).split("function ")[1].split("(")[0];

All we need:我们所需要的:

  1. Wrap a constant in a function (where the name of the function equals the name of the object we want to get)将一个常量包裹在一个函数中(其中函数的名称等于我们想要获取的对象的名称)
  2. Use arrow functions inside the object在对象内部使用箭头函数

 console.clear(); function App(){ // name of my constant is App return { a: { b: { c: ()=>{ // very important here, use arrow function console.log(this.constructor.name) } } } } } const obj = new App(); // usage obj.abc(); // App // usage with react props etc, // For instance, we want to pass this callback to some component const myComponent = {}; myComponent.customProps = obj.abc; myComponent.customProps(); // App

在运行时获取类名的最有效方法

let className = this.constructor.name

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM