[英]Redirecting command output to a variable in bash fails
I'm trying to redirect command output to a variable:我正在尝试将命令输出重定向到一个变量:
OUTPUT=$(sudo apache2ctl configtest)
and then to read it:然后阅读它:
echo $OUTPUT
When running it the output is the following:运行时输出如下:
19:19:12 user@user ~ OUTPUT=$(sudo apache2ctl configtest)
Syntax OK
Syntax OK
But the variable stays blank.但变量保持空白。 I've tried the same for other commands and everything works fine.
我已经对其他命令尝试了相同的方法,一切正常。
OUTPUT=$(ls -l)
This writes file list to variable OUTPUT
so that it can be read later.这会将文件列表写入变量
OUTPUT
以便稍后读取。 What should i do to make it work?我应该怎么做才能使它工作?
Maybe the output goes to stderr
, not stdout
?也许输出到
stderr
,而不是stdout
? Try this:尝试这个:
OUTPUT=$(sudo apache2ctl configtest 2>&1)
For nginx possible situation when configtest can be successful with error in config files.对于 nginx 可能的情况,当 configtest 可以成功但配置文件中出现错误时。 Example:
例子:
nginx: [warn] conflicting server name "test.com" on 0.0.0.0:80, ignored
nginx: the configuration file /etc/nginx/nginx.conf syntax is ok
nginx: configuration file /etc/nginx/nginx.conf test is successful
for correct check errors in bash scripts need use:为了正确检查 bash 脚本中的错误,需要使用:
if [[ $((sudo /sbin/service nginx configtest) 2>&1 | grep "failed\|warn" ) ]]; then
echo "ERROR!!!"
else
echo "OK!!!"
fi
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