如何使用PHP删除MySQL数据库中的所有记录？

Question

I would like to scrap all my records in a database. I want to use just a PHP script, not PhpMyAdmin. I have will be using a MySQL database administrator account. What SQL query should I use?

Answer 1

You could run a query:

/* Assumes the existence of a few key variables
   and further, that your user has the appropriate permissions */

mysql_connect( $host, $user, $pass ) or die( mysql_error() );
mysql_select_db( $db ) or die( mysql_error() );

mysql_query( "TRUNCATE TABLE tablename" );

Or

mysql_query( "DELETE FROM tablename" );

CAUTION!

These queries will result in all records being deleted. If you want only certain records to be dropped, add a where clause:

mysql_query( "DELETE FROM tablename WHERE userid = 5" );

Answer 2

To completely empty the database, dropping all tables (if that's what you really want to do), run this PHP script.

<?php

header('Content-Type: text/plain');

$link = mysqli_connect('host', 'username', 'password');
mysqli_select_db($link, 'database_name');
mysqli_set_charset($link, 'utf8');

$sql = 'SHOW TABLE STATUS FROM `database_name`;';
$result = mysqli_query($link, $sql);

$rows = array();
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    $rows[] = $row;
}

$n = 0;
foreach ($rows as $row) {
    $sql = 'DROP TABLE IF EXISTS `' . mysql_real_escape_string($row['Name']) . '`;';
    mysqli_query($link, $sql);
    ++$n;
}

echo $n . 'tables dropped' . PHP_EOL;
exit(__FILE__ . ': ' . __LINE__);