从类型int分配类型char [2]时编译“不兼容类型”的错误

Question

I am having the above mentioned compile error. The line of code is this:

if ((strcmp(tempDept, data[1].Dept)==0) && tempCourse == data[i].course){
            if (tempDay = data[i].meet_days &&
                tempTime == data[i].start.hour){  //<---This line
                    printf("this worked");
            }
        }

Here is my structs declarations:

typedef enum {MW, TR} days;

typedef struct {
  int hour, min;
} Time;

typedef struct {
  char Dept[5];
  int course, sect;
  days meet_days;
  Time start, end;
  char instr[20];
} sched_record;

And here is my list off variables:

int switchInput;
int i = 0;
int tempCourse = 0;
char tempDept[5];
char tempDay[2];
int tempTime;
//char tempTime[1];
FILE *filePointer;
sched_record data[MAX_RECORD];

Can someone tell me how to fix this?

Answer 1

if (tempDay = data[i].meet_days

你错过了双等号==

Answer 2

tempDay = data[i].meet_days

This couses a problem because tempDay is char array of length 2 and meet_days is enum days . And in C constants in enums are just of int type. Another problem that you can't assign int to char array itself. Maybe you wanted an equal sign == ? Now you must think how to convert int enum value to char[2] . One way is use sprintf() to accomplish that. But concrete implementation depends on your interpretation of enum constants.