[英]array is overwritten by the last element in php
The result stored in $g
is 1 and 2. The following code I've written below, my $array['music']
stores only the last element that is 2. But what I want is to execute my sql query 2 times under foreach and match the value of $g
which is 1 and 2 with mu_id
( mu_id
is the column name from another table music
) and store all the rows data of row 1 and 2 in to $array['music']
. 存储在
$g
的结果是1和2。下面我写的以下代码$array['music']
仅存储最后一个元素2。但是我想要的是在下面执行2次sql查询foreach并将$g
的值1和2与mu_id
( mu_id
是来自另一种music
的列名),并将行1和2的所有行数据存储到$array['music']
。
It is storing only for the second row (2) not for 1 or it is overwriting it when it is executing for the second time inside loop. 它仅为第二行(2)存储而不为1存储,或者在第二次在循环内执行时覆盖它。 If there is any logic to make it work then please let me know.
如果有任何逻辑可以使其正常工作,请告诉我。
foreach($genre as $g)
{
echo $g;
echo "<br>";
$array['music'] = $m -> where('mu_id', $g ) -> get();
}
You're redeclaring the entire array each time rather than adding to it, use this instead: 您每次都在重新声明整个数组,而不是在整个数组中进行声明,而应使用以下代码:
foreach($genre as $g)
{
$array['music'][] = $m->where('mu_id', $g)->get();
}
Or even better, less queries: 甚至更好,查询更少:
$array['music'] = $m->where_in('mu_id', $genre)->get();
如果要将所有数据存储在数组中,则应使用$array['music'][]
而不是$array['music']
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