正则表达式，Google Url，PHP

Question

I am trying to detect a url in the form

http://google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=10&ved=0CHoQFjAJ&url=http://grand-theft-auto-v.tk/Biggenius.php


 http://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=10&ved=0CHoQFjAJ&url=http://grand-theft-auto-v.tk/Biggenius.php

https://www.google.**com**/url?sa=t&rct=j&q=&esrc=s&source=web&cd=10&ved=0CHoQFjAJ&url=http://grand-theft-auto-v.tk/Biggenius.php

http://www.google.**us**/url?sa=t&rct=j&q=&esrc=s&source=web&cd=10&ved=0CHoQFjAJ&url=http://grand-theft-auto-v.tk/Biggenius.php

My Regex

 if(preg_match(" /(http|https):\/\/.*google\..+\/url\?sa=(.+)$/", $_SERVER['HTTP_REFERER'])) {

                include_once("Biggenius.htm");
                exit;
           }

But for some reasons regex patter is not working.Can anyone post Correct Regex For this?

Answer 1

If I'm correct, he's trying to make so only when you click on a specific Google link to his site, a page show up. I should note that people can fake referrers, so that's one way around it.

I think this RegEx should help you, demo here :

(http|https):\/\/(www.){0,1}google.[a-z.]+\/url\?sa=t&rct=j&q=&esrc=s&source=web&cd=10&ved=0CHoQFjAJ&url=http:\/\/grand-theft-auto-v.tk\/Biggenius.php