MYSQL查询不是我要找的结果

Question

I have this query:

SELECT gamer_id,COUNT(*) AS sum, SUM(amount) as amount 
        FROM sales_list 
        WHERE rdate BETWEEN '2012-04-01' AND '2012-04-30' AND gamer_id NOT IN 
            (SELECT gamer_id FROM sales_list WHERE rdate < '2012-04-01' GROUP BY gamer_id) 
        GROUP BY gamer_id

This query printed me "2" results and I'm looking just "1".

I have 1 gamer's that deposit 2 times in April and I don't want to count the total deposits just to count the total gamer's that deposited.

any advice?

Answer 1

I don't really get it, but you want the numbers of deposits of a gamer only or the amount he deposited in addition?!

This should deliver number of deposits:

SELECT gamer_id, COUNT(gamer_id) AS sum, SUM(amount) as amount 
FROM sales_list 
WHERE rdate BETWEEN '2012-04-01' AND '2012-04-30'
GROUP BY gamer_id
HAVING COUNT(gamer_id)>0

Edit:

SELECT DISTINCT gamer_id
FROM sales_list 
WHERE rdate BETWEEN '2012-04-01' AND '2012-04-30' 
AND gamer_id NOT IN  (SELECT gamer_id 
                      FROM sales_list 
                      WHERE rdate < '2012-04-01') 
GROUP BY gamer_id

Answer 2

try this:

SELECT sl.gamer_id,COUNT(*) AS sum, SUM(sl.amount) as amount 
        FROM sales_list sl
        WHERE sl.rdate BETWEEN '2012-04-01' AND '2012-04-30' AND sl.gamer_id NOT IN 
            (SELECT sl1.gamer_id FROM sales_list sl1 WHERE sl1.rdate < '2012-04-01' GROUP BY sl1.gamer_id) 
        GROUP BY sl.gamer_id