如何删除字符串后面的所有标点符号？

Question

It's for a game in which the user can input a value like "Iced tea.." I would like to manipulate the string to return "Iced tea" without the trailing punctuation marks.

Looking for most elegant / simplest python solution.

Tried

def last_character(word):
  if word.endswith('.' or ','):
      word = word[:-1]
  return word 

which works if there's only one punctuation mark at the end. But it's not all-encompassing.

Found a Java solution :

String resultString = subjectString.replaceAll("([a-z]+)[?:!.,;]*", "$1");

Answer 1

>>> 'words!?.,;:'.rstrip('?:!.,;')
'words'

Answer 2

In this case, rstrip is probably what you want. But in general, it's not hard to translate something like that Java into Python. A direct translation would look like this:

import re
subject_string = 'Iced tea..'
result_string = re.sub('([a-z]+)[?:!.,;]*',r'\1',subject_string)

Answer 3

import string
s='aaa...,'
count= 0
>>> for l in s[::-1]:
...     if l in string.punctuation:
...             count = count +1
...     else:
...             break
>>> s[:c]
'aaa'