[英]How to get the numeric part from a string using T-SQL?
I have the following string. 我有以下字符串。
Input
--------------
2030031469-NAI
To get the numeric part, I am using the following script 要获取数字部分,我使用以下脚本
declare @str varchar(50)= '2030031469-NAI'
Select
@str
,SUBSTRING(@str, 1, NULLIF(CHARINDEX('-', @str) - 1, -1))
,Left(@str,PATINDEX('%-%',@str)-1)
to get the following output 获得以下输出
Output:
----------
2030031469
Is there any other easy/elegant way of doing the same? 有没有其他简单/优雅的方式做同样的事情?
select left(@str, patindex('%[^0-9]%', @str+'.') - 1)
Please check with this, i used in my project for extracting phone numbers 请检查一下,我在我的项目中用于提取电话号码
CREATE Function [dbo].[RemoveNonNumericCharacters](@Temp VarChar(1000))
Returns VarChar(1000)
AS
Begin
While PatIndex('%[^0-9]%', @Temp) > 0
Set @Temp = Stuff(@Temp, PatIndex('%[^0-9]%', @Temp), 1, '')
Return @TEmp
End
In case your string start with alphabet and end with number like ERT-123 如果您的字符串以字母开头并以ERT-123之类的数字结尾
you can use this query: 你可以使用这个查询:
(select substring(@str,patindex('%[0-9]%', @str),len(@str)))
To extract number from an unformatted string 从未格式化的字符串中提取数字
DECLARE @Text NVARCHAR(100)= 'extract only 23124R integer @#%%'
SELECT SUBSTRING(@Text, PATINDEX('%[0-9]%',@Text), PATINDEX('%[^0-9]%',SUBSTRING(@Text, PATINDEX('%[0-9]%',@Text), LEN(@Text)))-1) [ONLY_INT]
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