关于将函数作为参数传递的好奇心-C ++

Question

suppose you have the following method:

double * myMethod(double (*f)(double[]), double *x, int size)
{
    //do something and return
}

Why can't I write as follows?

double * myMethod(double (*f)(double *), double *x, int size)
{
    //do something and return
}

replacing the [] with * ?

Answer 1

You can, but because arrays deprecate the pointers, they actually have the same signature, so if you're getting an error it's because you're trying to redefine the function:

http://ideone.com/E1Z7B works because I renamed the second function.