[英]How to extract string in Java
For example, I have a string as below: 例如,我有一个字符串如下:
<http://www.w3.org/2000/01/rdf-schema#label> "Telecommunications law"@en <http://en.wikipedia.org/wiki/>
What is the easiest way to extract the substring: 提取子字符串的最简单方法是什么:
Telecommunication law
Please note that the substring contains a space. 请注意,子字符串包含一个空格。
You could use Pattern and Matcher : 您可以使用Pattern和Matcher:
Pattern p = Pattern.compile("\".*\"");
Matcher m = p.matcher(s);
if(m.find()){
String resultString = m.group();
}
In your case, resultString will contain ["Telecommunications law"] and you can trim the double quotes if you don't want to keep them. 在您的情况下,resultString将包含[“电信法”],如果您不想保留双引号,则可以修剪双引号。
String.split()
the string on "
, and select the second element in the returned array: String.split()
对串"
,并选择返回的数组中的第二个元素:
String tokens[] = yourString.split("\"");
// tokens[1] will contain Telecommunications law
what do you mean "extracting the string" ? 你是什么意思“提取字符串”?
getting the first occurence of the string is by: 获取字符串的第一次出现是通过:
int index = string.indexOf("Telecommunications law");
the most efficient way of getting what is in between the first parenthesis and the second is by: 获取第一个括号和第二个括号之间的内容的最有效方法是:
final String test="http://www.w3.org/2000/01/rdf-schema#label \"Telecommunications law\"@en http://en.wikipedia.org/wiki/";
final int firstIndex=test.indexOf('\"');
final int lastIndex=test.indexOf('\"',firstIndex+1);
final String result=test.substring(firstIndex+1,lastIndex);
System.out.println(result);
public static void main(String[] args) {
String str = "http://www.w3.org/2000/01/rdf-schema#label \"Telecommunications law\"@en http://en.wikipedia.org/wiki/" ;
String temp = str.substring(str.indexOf('\"')+1, str.indexOf('\"',str.indexOf('\"')+1));
System.out.print(temp);
}
public static void main(String args[]){
String yourString = "<http://www.w3.org/2000/01/rdf-schema#label> \"Telecommunications law\"@en <http://en.wikipedia.org/wiki/>";
String tokens[] = yourString.split("\"");
for(int i = 0; i < tokens.length; i++){
if(tokens[i].equals("Telecommunications law")){
System.out.println(tokens[i]);
}
}
}
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