[英]Python function returns None, unclear why
I am pretty new to python and am hitting an issue I cannot explain. 我是python的新手,遇到了我无法解释的问题。 I have tried searching through the forum answers here, but what I am finding does not match up with my situation. 我尝试在此处搜索论坛答案,但是发现的情况与我的情况不符。 It feels like I am missing something pretty basic, but I'm not seeing it (obviously...) 感觉好像我缺少一些基本的东西,但是我没有看到(显然...)
This code runs the way I expect: 这段代码按照我期望的方式运行:
import string
mults = [1,2,3,4,6,7,9,10,12,15,16,19,21,22,24]
def factor_exp(lst):
if lst[-1] == 1:
lst.pop()
return lst+[1]
if lst[-1] == 2:
lst.pop()
return lst+[1,1]
else:
return "Should never get here"
print factor_exp([1])
print factor_exp([2])
print factor_exp([1,2])
This returns: 返回:
>>>
[1]
[1, 1]
[1, 1, 1]
Which is what I want. 这就是我想要的。
I thought using append and extend on the list inside the function would work also. 我认为在函数内的列表上使用追加和扩展也可以。 One "append" added near the bottom of the code. 在代码底部附近添加了一个“追加”。
import string
mults = [1,2,3,4,6,7,9,10,12,15,16,19,21,22,24]
def factor_exp(lst):
if lst[-1] == 1:
lst.pop()
return lst+[1]
if lst[-1] == 2:
lst.pop()
return lst.append([1,1])
else:
return "Should never get here"
print factor_exp([1])
print factor_exp([2])
print factor_exp([1,2])
But this returns: 但这返回:
>>>
[1]
None
None
Why are the "None's" appearing? 为什么出现“无”? Thanks in advance for any help or insights. 在此先感谢您的帮助或见解。
I didn't study your code, but I'd say that it's for this line: 我没有研究您的代码,但我想说的是:
return lst.append([1,1])
list.append()
always returns None
. list.append()
始终返回None
。
So lst.append([1,1])
will append [1,1]
to lst
and return None
. 所以lst.append([1,1])
会将[1,1]
附加到lst
并返回None
。
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