如何通过OpenLayers地图中的ID获取弹出窗口

Question

When initial the map, I created many popup for features 初始地图时，我为功能创建了许多弹出窗口

var popup= new OpenLayers.Popup.FramedCloud(
    id, //id
    new OpenLayers.LonLat(msg.reviseLng, msg.reviseLat),
    new OpenLayers.Size(160,100),
    '<html></html>',
    null,
    true);
    popup.autoSize=false;
    map.addPopup(popup);

but I can not get a exist popup when I location a point ,I want get it by it's id and show it, please help me 但是当我定位一个点时，我无法获得一个存在的弹出窗口，我想通过它的id来显示它并显示它，请帮助我

Answer 1

The idea should be: when the user click on a certain point recognized by you, the popup should be displayed, isn't it? 这个想法应该是：当用户单击您识别的某个点时，应该显示弹出窗口，不是吗？

You can do it in this way: 您可以通过以下方式进行操作：

map.events.register("click", map , function(e){
   // Look for point... (your code)

   // Point detected!

   // now we need to take the popup identified by 'popupid' identifier and show it
   for(var i=0; i<map.popups.length; i++){
      if(map.popups[i].id == myid){
         map.popups[i].show();
         break;
      }
   }
});

如何通过OpenLayers地图中的ID获取弹出窗口

问题描述

1 个解决方案

解决方案1
0 2012-05-12 12:06:27

如何通过OpenLayers地图中的ID获取弹出窗口

问题描述

1 个解决方案

解决方案1 0 2012-05-12 12:06:27

解决方案1
0 2012-05-12 12:06:27