如何连接三个表并添加“AND”运算符？

Question

Being a Rookie i am a bit lost as to how to nail this. I am trying to join three tables. This is the table structure:

Accounts Table: 

1) id
2) User_id (Id given to user upon sign up)
3) Full_name 
4) Username
5) Email
6) Password

Contacts Table: 

1) My_id (This is the user who added friend_id)
2) Contact_id (this is the contact who was added by my_id)
3) Status (status of relationship)

Posts Table: 

1) Post_id
2) User_posting (this is the user who posted it)
3) Post_name
4) User_allowed (this is where its specified who can see it)

Here is the code structure i have:

<?php

$everybody = "everybody";
$sid = "user who is logged in.";

$sql = <<<SQL
SELECT DISTINCT contacts.contact_id, accounts.full_name, posts.post_id, posts.post_name
FROM contacts, accounts, posts
WHERE
    (contacts.my_id = '$sid'
      AND contacts.contact_id = accounts.user_id)
    OR (contacts.my_id = '$sid'
      AND contacts.contact_id = accounts.user_id)
    OR (posts.user_posting = '$sid'
      AND contacts.contact_id = accounts.user_id
      AND posts.user_allowed = '$everybody')
    OR (posts.user_id = '$sid'
    AND contacts.user_id = accounts.user_id
    AND posts.user_allowed = '$everybody')

LIMIT $startrow, 20;


$query = mysql_query($sql) or die ("Error: ".mysql_error());

$result = mysql_query($sql);

if ($result == "")
{
echo "";
}
echo "";


$rows = mysql_num_rows($result);

if($rows == 0)
{
print("");

}
elseif($rows > 0)
{
while($row = mysql_fetch_array($query))
{

$contactid = htmlspecialchars($row['contact_id']);
$name = htmlspecialchars($row['full_name']);
$postid = htmlspecialchars($row['post_id']);
$postname = htmlspecialchars($row['post_name']);

// If $dob is empty
if (empty($contactid)) {

$contactid = "You haven't added any friends yet.";
}


print("$contactid <br>$postname by $name <br />");
}

}

The problem is that the query shows me my posts plus all posts from friends.

What am i doing wrong?

Answer 1

Should be like this (Not thoroughly checked):

SELECT DISTINCT contacts.contact_id, 
                accounts.full_name,
                posts.post_id, 
                posts.post_name 
FROM contacts
INNER JOIN accounts ON accounts.id = contacts.id
INNER JOIN posts ON posts.User_posting = accounts.id /* (where'd get posts.user_id btw ) */
WHERE contacts.my_id = $sid
      AND posts.user_allowed = $everybody
LIMIT $startrow, 20

Answer 2

Assuming you only want to show your friends' posts (and not your own):

$everybody = "everybody";
$sid = user who is logged in.  

$sql = "SELECT a.User_id, a.Full_name, p.Post_id, p.Post_name
FROM posts p
INNER JOIN accounts a ON a.User_id = p.User_posting
INNER JOIN contacts c ON c.My_id = '$sid' AND c.Contact_id = a.User_id
WHERE p.User_allowed = '$everybody'
LIMIT $startrow, 20";

EDIT: Explaining the query.

1. The query SELECT s certain fields used for output
2. FROM the posts table since the result should contain a row for each post.
3. That base table is JOIN ed with accounts table to get the data of the posting user and
4. additionally JOIN ed with contacts table so we can filter to only have posting users that are also friends added by the user in question.
5. An additional filter is on the allowed value and
6. for pagination purposes we have an offset defined by $startrow .