这有什么意义：*（void **）（＆fptr）= dlsym（handle，“my_function”）;`

Question

The code comes from this page: http://pubs.opengroup.org/onlinepubs/009695399/functions/dlsym.html

Can you help me understand this? It takes the address of the function pointer, casts it to void** and then dereferences it. I don't know why it has to work like this.

I appreciate your help! Until now, the only advice I have gotten was "read it from right to left" or something like "read it in cycles from right to left".

Answer 1

The meaning of the code is:

1. Take the address of fptr . The type of this expression is pointer-to-pointer-to-function (of some specific type).
2. Cast that pointer expression to "pointer to pointer to void".
3. Dereference that pointer to access the object fptr as if it were an object of type void * .
4. Assign the result of the right to the lvalue obtained in step 3.

Unfortunately, whoever wrote this example in POSIX was on crack, because step 3 violates the aliasing rules of the C language and thus invokes undefined behavior. In particular, real-world compilers will optimize this code in ways that breaks the intended usage.

What the author of this example was trying to achieve was avoiding casting the right-hand side from pointer to void to pointer to function . This is based on a claim that the C standard requires this cast to generate a warning, but I have searched thoroughly for such a requirement and can find no such requirement.

If such a problem really does exist (the warning requirement), then the only way to silence the warning without invoking undefined behavior (like the bad example in the text of POSIX) is to do this:

void (*fptr)(); // or whatever function pointer type you want
void *temp = dlsym(handle, "my_function");
memcpy(&fptr, &temp, sizeof fptr);

Answer 2

The function returns an a function pointer. That code says hey take my function pointer variable give me the address of it. Cast it to void ** . Now deference the void ** and set the value of the void * = to the pointer I got from the call.

Answer 3

*(void **)(&fptr) = dlsym(handle, “my_function”);

To make this simpler,

fptr is a pointer.

&fptr is the address of that pointer.

you are typecasting it to a pointer to a pointer to a void

and then reference and assign the return value from function.