使用sed在句点后插入空格

Question

I've got a bunch of files that have sentences ending like this: \\@.Next sentence . I'd like to insert a space after the period.

Not all occurrences of \\@. do not have a space, however, so my regex checks if the next character after the period is a capital letter.

Because I'm checking one character after the period, I can't just do a replace on \\@. to \\@. , and because I don't know what character is following the period, I'm stuck.

My command currently:

sed -i .bak -E 's/\\@\.[A-Z]/<SOMETHING IN HERE>/g' *.tex

How can I grab the last letter of the matching string to use in the replacement regex?

EDIT: For the record, I'm using a BSD version of sed (I'm using OS X) - from my previous question regarding sed , apparently BSD sed (or at least, the Apple version) doesn't always play nice with GNU sed regular expressions.

Answer 1

The right command should be this:

sed -i.bak -E "s/\\\@.(\S)/\\\@. \1/g" *.tex

Whith it, you match any \\@ followed by non whitespace ( \\S ) and insert a whitespace (what is made by replacing the whole match with '\\@ ' plus the the non whitespace just found).

Answer 2

Use this sed command:

sed -i.bak -E 's/(\\@\.)([A-Z])/\1 \2/g' *.tex

OR better:

sed -i.bak -E 's/(\\@\.)([^ \t])/\1 \2/g' *.tex

which will insert space if \\@. is not followed by any white-space character (not just capital letter).

Answer 3

I think the following would be correct:

s/\\@\.[^\s]/\\@. /g

Only replace the expression if it is not followed by a space.

Answer 4

This might work for you:

sed -i .bak -E 's/\\@\. \?/\\@. /g' *.tex

Explanation:

If there's a space there replace it with a space, otherwise insert a space.