[英]Oracle - Comparing dates
I have this Oracle procedure: 我有这个Oracle程序:
CREATE OR REPLACE PROCEDURE xmas
IS
CURSOR curUser IS SELECT userID, coins FROM Users;
thisUser curUser%ROWTYPE;
d VARCHAR(7);
CURSOR curDate IS SELECT TO_CHAR(sysdate, 'DD-MON') FROM DUAL;
BEGIN
OPEN curDate;
FETCH curDate INTO d;
CLOSE curDate;
IF ((TO_DATE(d)) = (TO_DATE('25-DEC'))) THEN
OPEN curUser;
LOOP
FETCH curUser INTO thisUser;
EXIT WHEN (curUser%NOTFOUND);
thisUser.coins := thisUser.coins + 5.00;
UPDATE Users SET coins = thisUser.coins WHERE userID = thisUser.userID;
END LOOP;
CLOSE curUser;
END IF;
END xmas;
and when I call it, I get this error: 当我调用它时,我收到此错误:
ORA-01840: input value not long enough for date format. ORA-01840:日期格式的输入值不够长。
Tried different comparison methods for hours and nothing else has worked. 尝试了几个小时的不同比较方法,没有其他工作。 What's the problem??
有什么问题??
You need to specify a date format for Oracle to know what actually '25-DEC' means. 您需要为Oracle指定日期格式,以了解实际上'25 -DEC'的含义。
select TO_DATE('25-DEC', 'DD-MON') from dual;
The problem should be on this line: 问题应该放在这一行:
IF ((TO_DATE(d)) = (TO_DATE('25-DEC'))) THEN
As a note, it seems to me that you are also making a lot of unnecessary conversions. 作为一个注释,在我看来,你也做了很多不必要的转换。 I don't know if this is an educational attempt, but why not just run the update below:
我不知道这是否属于教育尝试,但为什么不运行以下更新:
update USERS
set
coins = coins + 5
where
to_char(sysdate, 'DD-MON') = '25-DEC';
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