[英]Replace items in list, python
I have a list of strings like this: 我有一个像这样的字符串列表:
Item_has_was_updated_May_2010
Item_updated_Apr_2011
Item_got_updated_Sept_2011
I want to iterate through the list of string and update the last 2 parts of the string. 我想迭代字符串列表并更新字符串的最后两部分。 The month and the year.
一个月和一年。 The rest of the string I want to remain the same.
字符串的其余部分我想保持不变。 The month and year will be taken from variables I have set earlier in my script, so let's call the month x and the year y.
月份和年份将取自我之前在脚本中设置的变量,因此我们称之为月份x和年份y。
My approach is to: 我的方法是:
The month and year will be taken from variables I have set earlier in my script, so let's call the month x and the year y. 月份和年份将取自我之前在脚本中设置的变量,因此我们称之为月份x和年份y。
If anyone can suggest a an approach, it is appreciated. 如果有人可以建议一种方法,我们将不胜感激。
You can do it without regular expressions by using str.rsplit
: 您可以使用
str.rsplit
在没有正则表达式的情况下执行此str.rsplit
:
yourlist = [s.rsplit('_', 2)[0] + '_' + x + '_' + y for s in yourlist]
See it working online: ideone 看到它在线工作: ideone
If you want to use formatting instead of string concatenation, try this: 如果要使用格式而不是字符串连接,请尝试以下操作:
yourlist = ['{}_{}_{}'.format(s.rsplit('_', 2)[0], x, y) for s in yourlist]
I don't think you really need 're'. 我不认为你真的需要'重新'。
You could use something like this: 你可以使用这样的东西:
m="dec"
y=2012
l=["Item_has_was_updated_May_2010",
"Item_updated_Apr_2011",
"Item_got_updated_Sept_2011"]
r=[]
for s in l:
t=s.split("_")
r.append("_".join(t[:-2])+"_%s_%s"%(m,y))
lst = [
'Item_has_was_updated_May_2010',
'Item_updated_Apr_2011',
'Item_got_updated_Sept_2011',
]
month='Sep';year='2012'
for s in lst:
list=s.split('_')
list[-2:]=(month,year)
r=''
for a in list:
r=r+"%s_"%a
r=r[:-1]
print r
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