[英]Get Nearest Date in php
I have list of events so each event start date to end date so each event have list of schedules between events start date and end date I need to get only first nearest date I mean first event schedule date. 我有事件列表,所以每个事件的开始日期到结束日期,所以每个事件都有事件开始日期和结束日期之间的时间表列表。我只需要获取第一个最近的日期,即第一个事件时间表的日期。
Here is my code 这是我的代码
SELECT
s.schedule_id, s.schedule_start_time, s.schedule_end_time, s.schedule_topic, s.Parallel,
c.speaker_name
FROM schedule_table AS s, speaker_profile_table AS c
WHERE
s.event_id='23'
OR s.schedule_date LIKE '%2012-06-07%'
AND c.speaker_id = s.speaker_id
ORDER BY s.schedule_start_time ASC
Here I get all schedules like this 在这里,我得到了所有这样的时间表
schedule1:2012-06-06, schedule2:2012-06-06, schedule3:2012-06-08
时间表1:2012-06-06,时间表2:2012-06-06,时间表3:2012-06-08
Here I need only schedule1 and schedule2 only I don't need schedule3 how can i get this please guide me 在这里,我只需要schedule1和schedule2我就不需要schedule3我怎么能得到这个,请指导我
Thanks for advance 谢谢前进
If I understand what you want correctly, this should do the job ( EDITED ): 如果我正确理解了您想要的内容,则应该执行此操作( EDITED ):
SELECT
s.schedule_id, s.schedule_start_time, s.schedule_end_time, s.schedule_topic, s.Parallel,
c.speaker_name
FROM schedule_table s
LEFT JOIN speaker_profile_table c ON c.speaker_id = s.speaker_id
WHERE s.schedule_date = (
SELECT schedule_date
FROM schedule_table
WHERE
event_id = '23'
OR schedule_date LIKE '%2012-06-07%'
ORDER BY schedule_date ASC
LIMIT 1
)
ORDER BY s.schedule_start_time ASC
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