[英]Get unique records from a table + sum if the record is not distinct
I have a table in mysql like below : 我在mysql中有一个如下表:
Table name : Emp 表名:Emp
Emp Name | Time
_______________
ABC | 1
ABC | 2
ABC | 3
PQS | 4
XYZ | 5
I want the output as below 我想要以下输出
Emp Name | Time
_______________
ABC | 6
PQS | 4
XYZ | 5
As you can see only the unique Emp names are returned and the time is added for each instance of Emp name. 如您所见,仅返回唯一的Emp名称,并且为Emp名称的每个实例添加时间。
This might help: 这可能会有所帮助:
SELECT
EmpName,
SUM(Time) AS Total
FROM
table1
GROUP BY
EmpName
This is a rudimentary aggregate SUM()
grouping by Emp Name
: 这是按Emp Name
分组的基本汇总SUM()
:
SELECT
EmpName,
SUM(Time) AS Time
FROM Emp
GROUP BY EmpName
ORDER BY EmpName
Review the MySQL documentation on aggregate functions and the use of GROUP BY
clauses. 查看有关聚合函数和GROUP BY
子句使用的MySQL文档 。
Note, if your column name is actually Emp Name
with the space, you will need to quote it with backticks as in: 注意,如果您的列名称实际上是带空格的Emp Name
,则需要用反引号将其引起来,如下所示:
SELECT
`Emp Name`,
SUM(Time) AS Time
FROM Emp
GROUP BY `Emp Name`
ORDER BY `Emp Name`
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.