如何选择与其对应的最早日期和数据

Question

I have a very simple question that's kicking my ass.

CUSTNMBR   |  first_date |  SOPNUMBE
----------------------------------------
3344771005 |  2012-05-03 |  334471961748         
3344771005 |  2012-04-04 |  334476873726

In the above table i want to return the earliest date along with the custnumbr and sopnumbe so it'll look like this

3344771005 |  2012-04-04 |  334476873726

I used this

Select a.CUSTNMBR, min(a.Tax_Date) as first_date, a.SOPNUMBE
from SOP30200 as a
where a.CUSTNMBR = '3344771005'
Group by a.CUSTNMBR, a.SOPNUMBE

but it returns all variables and if I knock off the a.sopnumbe in group it errors out.

Answer 1

Try this:

Select top 1 a.CUSTNMBR, a.Tax_Date as first_date, a.SOPNUMBE 
from SOP30200 as a 
where a.CUSTNMBR = '3344771005' 
order by a.Tax_Date asc

Answer 2

Try

Select TOP 1 a.CUSTNMBR, min(a.Tax_Date)as first_date, a.SOPNUMBE
from SOP30200 as a
where a.CUSTNMBR = '3344771005'
Group by a.CUSTNMBR, a.SOPNUMBE'
ORDER BY 2 ASC