正则表达式使用PHP将文件路径替换为字符串中的文件名

Question

I've got a css string like this :

$string = "div#test {background: url(images/test.gif); width:100px; } div#test2 {background: url(../images/test2.gif); } ";

Basically I want to able to replace everything between url () to just the filename. So that it eventually looks like :

$string = "div#test {background: url(test.gif); width:100px; } div#test2 {background: url(test2.gif); } ";

Sort of like applying basename but for relative urls and for all such instances.

Any ideas ?

Answer 1

Try this:

EDIT: I fixed the regex

<?php 

$string = "div#test {background: url(images/test.gif); width:100px; } div#test2 {background: url(../images/test2.gif); } ";
$output = preg_replace('/([\.\w\/]*\/)/', '', $string);

var_dump($output);
string(93) "div#test {background: url(test.gif); width:100px; } div#test2 {background: url(test2.gif); } "
?>

Answer 2

taking for granted that u have the file name stored in a variable, you could use

$string = preg_replace('~url(.+)~', 'url(' . $filename . ')', $string);

www.regular-expressions.info is a good source if u want to learn regular expressions

Answer 3

Assuming you don't have to match several div's in one string you could do something like this:

preg_replace(
    '@(.+url\()/?([^/]+/)*([^)]+)(\).+)@',
    '\\1\\3\\4',
    'div#test {background: url(images/test.gif); width:100px; }'
);

This also allows you to pass an array with multiple strings to replace