显示json数组中的所有项目

Question

I am trying to work with json and I almost have what I need. I am getting the correct info to display but I am having to pass each item of an array into a variable and then print the variable. I would like to display all of the items in each array. The json data I am working with is from an invoicing app ( www.curdbee.com ) and I am trying to show each invoice for a client. The data that I want to show is each line item, the line item price, and the total amount. Here is my code:

$(document).ready(function() {


    $.getJSON('https://nspirelab.curdbee.com/invoices.json?api_token=__token__', function(data){
        $.each(data, function(index, item){
            var total = item.invoice.total_billed;
            var lineItemName1 = item.invoice.line_items[0].name_and_description;
            var lineItemName2 = item.invoice.line_items[1].name_and_description;
            var lineItemPrice1 = item.invoice.line_items[0].price; 
            var lineItemPrice2 = item.invoice.line_items[1].price; 

            $('#results').append('<div class="lineItem"><ul><li>' + lineItemName1 + lineItemPrice1 + '</li><li>' + lineItemName2 + lineItemPrice2 + '</li><li>' + total + '</li></ul></div>');
        });

    });

});

Answer 1

A nested loop (or, in jQuery, a nested $.each() ) will do the job:

$.getJSON('https://nspirelab.curdbee.com/invoices.json?api_token=&client=104929', function(data){
   $.each(data, function(index, item){
      // create an empty ul (initially disconnected from the DOM)
      var $ul = $("<ul/>");

      // iterate over the line items
      $.each(item.invoice.line_items, function(i, lineItem) {
         // create an li element with the line details and append
         // it to the ul
         $ul.append( $("<li/>").html(lineItem.name_and_description + lineItem.price) );
      });

     // add the totals to the end of the ul
     $ul.append( $("<li/>").html(item.invoice.total_billed) );

     // create a new div, append the ul to it, and append the div to results
     $('#results').append( $('<div class="lineItem"/>').append($ul) );
   });
});

Answer 2

There are a ridiculous number of libraries out there to make things like this easier. Do a search for "javascript templates" to see what you've been missing and to learn about the various libraries you can choose between for this.

Answer 3

如果我理解你的问题，我认为你正在寻找的是某种迭代机制，尝试下划线.js 。