IBOutlet UIImageView

Question

I got 30 of these codes, with the same implementation:

// .h

@interface ViewController : UIViewController{
IBOutlet UIImageView *circle;
IBOutlet UIImageView *circle2;
}
@property (nonatomic, retain) IBOutlet UIImageView *circle;
@property (nonatomic, retain) IBOutlet UIImageView *circle2;

// .m

@implementation ViewController

@synthesize circle;
@synthesize circle2;

- (void)viewDidLoad
{
circle = [[UIImageView alloc]
                      initWithImage:[UIImage imageNamed:@"Circle.png"]];
circle2 = [[UIImageView alloc]
                      initWithImage:[UIImage imageNamed:@"Circle.png"]];
}

And somewhere in my code, Im adding it as a subview.

My problem is,Is there a way to make it shorter, for it to be maintainable.

Answer 1

If you use name like - Circle1.png , Circle2.png , then you can go for for loop for creating this in a loop.

Something like -

for (int i = 0; i < imageCount ; i++ ) {
    circle = [[UIImageView alloc]
                  initWithImage:[UIImage imageNamed:[NSString stringWithFormat: @"Circle%d.png" , i]]];
}

Answer 2

Is there a pattern to where you are putting these views in their superview? If so, you could use a for loop that goes to 30 and programmatically create the views and add them to their superview.

So for example:

   for (i = 0; i < 100; i++)
    {
        UIImageView* circle = [[UIImageView alloc]
                      initWithImage:[UIImage imageNamed:@"Circle.png"]];
        [self.view addSubview:circle];
    }

Would add 100 of the image views you would want. Of course you will need to adjust the positions of each of these views in the loop, but this is the general idea.

Answer 3

You can use one IBOutletCollection instead of 30 IBOutlets . You probably want to set the tag on each UIImageView though, so you can still tell them apart.

(This answer assumes you use a nib. Remove the lines where you instantiate the UIImageView s in viewDidLoad if so.)

Answer 4

创建此ViewController时，将框架作为参数传递。那是唯一更改rite ??的事情。图像是相同的，并且没有其他属性..它可能起作用