如何动态显示弹出消息

Question

I create a popup based on this post
but i want to create it based on visitor

I use below code in index.aspx page:

<div id='message' style="display: none;">
    <span>Wellcome 
        <%=UserName%></span> <a href="#" class="close-notify" onclick="closeNotice()">X</a>
</div>

and I show pop-up using jquery :

<script type="text/javascript">

$(document).ready(function() {
    $("#message").fadeIn("slow");

});

function closeNotice() {
    $("#message").fadeOut("slow");
}
</script>

now i want show this pop up only when user enter OR when CheckBox1.Checked value in "editor.aspx" is true...but time pop-up display every time that page load(even if user don't log in )

Answer 1

Why not create a Javascript variable and set it's value on !IsPostBack.

<script type="text/javascript">

var postBack = <%=IsPostedBack%>// you can use a variable from codebehind

if(postBack == false) $("#message").fadeIn("slow");

$("#message").fadeOut("slow");

</script>

Inside Page_Load function set IsPostedBack.