[英]Python regular expression split() string
I'm quite new to regular expression in python. 我对python中的正则表达式很新。 I have the following string and want to split them into five categories.
我有以下字符串,并希望将它们分为五个类别。 I just use the split() but it will just split according to white spaces.
我只是使用split()但它会根据空格分开。
s = "1 0 A10B 1/00 Description: This is description with spaces"
sp = s.split()
>>> sp
["1", "0", "A10B", "1/00", "Description:", "This", "is", "description", "with", "spaces"]
How can I write a regular expression to make it split like this: 如何编写正则表达式使其像这样拆分:
["1", "0", "A10B", "1/00", "Description: This is description with spaces"]
Can somebody help please? 有人可以帮忙吗? Thanks!
谢谢!
您可以简单地指定一些拆分:
s.split(' ', 4)
The second argument to split()
is the maximum number of splits to perform. split()
的第二个参数是要执行的最大拆分数。 If you set this to 4, the remaining string will be item 5 in the list. 如果将此值设置为4,则剩余的字符串将是列表中的第5项。
sp = s.split(' ', 4)
Not a perfect solution. 不完美的解决方案。 But for a start.
但是一开始。
>>> sp=s.split()[0:4]
>>> sp.append(' '.join(s.split()[4:]))
>>> print sp
['1', '0', 'A10B', '1/00', 'Description: This is description with spaces']
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