在Java中将十六进制数字字符串转换为双精度数字

Question

how can we convert hexadecimal number string to double-precision number in java ?

in matlab it's simple :

>> hex2num('c0399999a0000000')

ans =

  -25.6000

but could I do the same things in java also ?

I tried parseInt() but this number is not integer.

Answer 1

I think you want Double.longBitsToDouble , like this:

public class Test {
    public static void main(String[] args) {
        String hex = "c0399999a0000000";
        long longHex = parseUnsignedHex(hex);
        double d = Double.longBitsToDouble(longHex);
        System.out.println(d);
    }

    public static long parseUnsignedHex(String text) {
        if (text.length() == 16) {
            return (parseUnsignedHex(text.substring(0, 1)) << 60)
                    | parseUnsignedHex(text.substring(1));
        }
        return Long.parseLong(text, 16);
    }
}

(The fact that long is signed in Java makes this more awkward than you'd really want, but hey...)

Answer 2

首先加长，然后调用longBitsToDouble