测试CodeIgniter会话变量的正确方法是什么？

Question

Take the following code snippet. What is the best way to test to make sure the session variable isn't empty?

<?php if ($this->session->userdata('userID')) {
   $loggedIn = 1;
}
else {
   $loggedIn = 0;
} ?>

If later in my script, I call the following, the first prints properly, but on the second I receive Message: Undefined variable: loggedIn

<?php echo $this->session->userdata('userID'));
      echo $loggedIn; ?>

I've tried using !empty and isset , but both have been unsuccessful. I also tried doing the if/then statement backwards using if (!($this->session->userdata('userID')) , but no dice. Any thoughts?

Answer 1

Try doing the following instead:

<?php 
$loggedIn = 0;
if ($this->session->userdata('userID') !== FALSE) {
   $loggedIn = 1;
}
?>

If the error continues, you'll need to post more code in case you're calling that variable in another scope.

Answer 2

如果您的目的是查看是否设置了会话变量'userID' ，那么以下内容应该有效：

$this->session->userdata('userID') !== false

Answer 3

为什么不在会话中创建一个名为is_logged_in的布尔字段，然后检查如下：

if(false !== $this->session->userdata('is_logged_in'))

Answer 4

if($this->session->userdata('is_logged_in')) {
    //then condition
}

This is the proper way to test!