在Main函数中，try块引发异常后，如何使其继续执行下一个try块

Question

In Main function, after a try_block throws an exception the function is supposed to be break. My question is how can I make it keep on executing to the next try_block. Below I'm giving an example:

public static void main(String [] s){
    ABC aBC = new ABC();
    try {
        aBC.execute();
    } catch (Exception e) {
        _log.error(ErrorCodeEnum.ERROR,
                "XXXXXXX!!! in " + new Date(),e);
    }
    BCD bCD = new BCD();
    try {
        bCD.execute();
    } catch (Exception e) {
        _log.error(ErrorCodeEnum.ERROR,
                "YYYYYYYYYYY!!! in " + new Date(),e);
    }
}

Answer 1

The code should work as it stands - ie the second block should still get executed if the first block throws and catches an Exception.

However you might want to consider catching Throwable rather than Exception if you truly want to catch everything. In particular, java.lang.Error is not a subclass of Exception, but is a subclass of Throwable.

Answer 2

Just to be sure, you can wrap the statements you want executed in a finally block as follows:

ABC aBC = new ABC();

try
{
    aBC.execute();
}
catch (Exception e)
{
    _log.error(ErrorCodeEnum.ERROR, "XXXXXXX!!! in " + new Date(), e);
}
finally
{
    BCD bCD = new BCD();

    try
    {
        bCD.execute();
    }
    catch (Exception e)
    {
        _log.error(ErrorCodeEnum.ERROR, "YYYYYYYYYYY!!! in " + new Date(), e);
    }
}

The statements in the finally block will get executed regardless if an exception occurs in the outer try block.