firefox抱怨有效的json…看不见的无效字符？
[英]firefox complaining about valid json… invisible invalid character?
问题描述
I'm writing a php script that needs to load a 2D array into a js variable as json. 
我正在编写一个PHP脚本，该脚本需要将2D数组作为json加载到js变量中。 First i make the array then use json_encode to turn it into a string. 首先，我制作数组，然后使用json_encode将其转换为字符串。 Then I run a small bit of js to get it accessable on the client side. 然后，我运行一小段js以使其可在客户端访问。 Like so: 像这样：
$sBaseData = Filters::$sFilterBaseTypeData;
$sBaseData = str_replace('\r',' ',$sBaseData);
$sBaseData = str_replace('\n',' ',$sBaseData);
$sBaseData = str_replace('\t',' ',$sBaseData);
echo <<<HTML
<script type="text/javascript">
var validation_data = JSON.parse('$sBaseData');
</script>
HTML;
Firefox complains about an unexpected character here: Firefox在这里抱怨一个意外的字符：
var validation_data = JSON.parse('{"enumeration":{"js":"","msg":""},"date":{"js":" var parts = widget.value.split('-'); var d = new Date(parts[0],parts[1],parts[2]); PASS = (d.getDay()>=1); ","msg":"Invalid date. Please Enter a date in the format: YYYY-MM-DD"},"text":{"js":"","msg":"what did you do?"},"integer":{"js":"if (isNaN(widget.value)) { PASS = false; } else { intVal = parseInt(widget.value); PASS = (widget.value == intVal); } ","msg":"Please enter an integer value"},"decimal":{"js":"PASS = isNaN(widget.value); ","msg":"Please enter a number"},"group":{"js":"","msg":""},"dealer":{"js":"","msg":""}}')
I tried using http://jsonlint.com/ to find out which character was at fault but it says it's all valid and wonderful. 我尝试使用http://jsonlint.com/来找出哪个字符有问题，但是它说的确很有效。 I replaced some characters that were causing issues, is there anything else I should be replacing? 我替换了引起问题的某些字符，还有什么我需要替换的？
3 个解决方案
解决方案1
0 2012-05-28 07:36:46
Uh... 嗯...
var parts = widget.value.split('-');
Putting that in a string that uses single quotes will break it. 将其放在使用单引号的字符串中会破坏它。 Use a JSON encoder to output your JavaScript literal . 使用JSON编码器输出JavaScript文字 。
解决方案2
0 已采纳 2012-05-28 07:41:16
The problem is you have ' in your string while you are using ' to quote the string. 问题是你有'在您的字符串，而你正在使用'引用的字符串。
If your json string is valid, you don't need to parse it even. 如果您的json字符串有效，则甚至不需要解析它。 The below will work. 以下将工作。
echo <<<HTML
<script type="text/javascript">
var validation_data = {$sBaseData};
</script>
HTML;
解决方案3
0 2012-05-28 07:41:59
Your JSON is valid but in your js code the simple quote closes the parse function's argument. 您的JSON有效，但在js代码中，简单的引号关闭了解析函数的参数。
Try like this: 尝试这样：
"date":{"js":" var parts = widget.value.split(\'-\');
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