scala coding-style：根据可选值初始化val Seq

Question

I'm developing a simple function that should build a sql condition based on optional parameters that might not be present.

I'm trying to accomplish it using immutables values, and in and elegant and idiomatic way.

So far now I came with something like this:

val cond: Seq[String] = Nil ++ 
  (if (entity != "*") Seq("entity = {entity}") else Nil) ++
  (if (name != "*") Seq("name = {name}") else Nil) ++

val condition = 
  if (cond.size == 0) "" 
  else " where " + cond.mkString(" and ") + " "

So, I'm just mergins Seqs, if the value is not present I'm merging it with Nil

Working with a var I get something like:

var cond: Seq[String] = Seq();
if (entity != "*") cond = cond :+ "entity = {entity}"
if (name != "*") cond = cond :+ "name = {name}"

Which I find it to be more readable (I wonder if this second approach is not threadsafe because of the var)

I wanted to know what would be a scala idiomatic and elegant way to solve such a thing

-- edit

in the end, I settled down with this implementation:

val condition: String = {

  var cond: Seq[String] = Seq();

  if (entity != "") 
    cond = cond :+ "entity = {entity}"
  if (filter != "")
    cond = cond :+ """(name like {filter} or prev like {filter} or post like {filter})"""

  if (cond.size == 0) "" 
  else " where " + cond.mkString(" and ") + " "
}

Answer 1

Don't repeat yourself:

def seqIf(r: String, s: String) = if (r != "*") Seq("%s = {%s}".format(s,s)) else Nil

val cond = seqIf(entity, "entity") ++ seqIf(name, "name")

Not only strings:

def seqIf[A](p: Boolean, a: A) = if (p) Seq(a) else Nil

val cond = seqIf(entity != "*", "entity = {entity}") ++ 
  seqIf(name != "*", "name = {name}")

Answer 2

Another approach is to keep the mutable construction, but hidden in a block to avoid side effects:

val cond = {
  var cs = Seq[String]()
  if (entity != "*") cs = cs :+ "entity = {entity}"
  if (name != "*") cs = cs :+ "name = {name}"
  cs
}

Such construct is perfectly safe because the var is not accessible outside the block. You could also use a val with a mutable builder, for instance a ListBuffer . In that case. Just be sure you don't leak a mutable object out of the block:

import scala.collection.mutable.ListBuffer

val cond = {
  val cs = ListBuffer[String]()
  if (entity != "*") cs += "entity = {entity}"
  if (name != "*") cs += "name = {name}"
  cs.result() //Converts the ListBuffer into an immutable List
}

This is perfectly acceptable because the block itself is still "pure". This pattern appears in the Scala API.