大括号内的正则表达式值

Question

I have a random variable lets call it R inside a curly brackets like so:

{R}

I have tried to regex it with this:

{(.*?)//}

I then have this error

"Caused by: java.util.regex.PatternSyntaxException: 
Syntax error U_REGEX_RULE_SYNTAX near index 1:"

Indicator targeting {(.*?)} "("

I tried doing it without the brackets same error. This time indicator targets "."

Could someone help me find an alternate solution to regex items inside a curly brackets?

Answer 1

尝试转义大括号：

String regex = "\\{(.*?)\\}";

Answer 2

Curly brackets are used in regexp to define specific sequence repetition.

you have to escape them in the regexp.

\{(.*?)\}

should work better

Answer 3

Escape the {}s:

String regStr = "\\{.\\}";

I've found this interactive regex testing page useful in refining Java regular expressions.

Answer 4

Not entirely clear what you are trying to do by

\{.*\}

should work

Answer 5

You can escape special characters using a backslash \\ . See What special characters must be escaped in regular expressions? for more information (although there is no general rule). Try escaping the curly braces {} and slashes // .