将具有相同元素和属性名称的XML映射到Java对象

Question

I already searched for this particular issue, the closest thread i found was this one: Java/JAXB: Unmarshall XML elements with same name but different attribute values to different class members But it's still not exactly what i need, so i hope someone can help me with this.

I am doing a SOAP request on a Zimbra Collaboration Suite 7 Server to get a contact. The response is something like this:

<cn fileAsStr="Arthur, Spooner" f="" id="280" rev="1973" d="1338524233000" t="" md="1338524233" ms="1973" l="7"><meta/><a n="homePostalCode">93849</a><a n="lastName">Spooner</a><a n="birthday">1980-05-24</a><a n="homeStreet">Berkleystreet 99</a><a n="firstName">Arthur</a></cn>

I want to map this to a Java object, something like this:

public class Contact {
Integer id;
Integer rev;
String namePrefix;
String firstName;
String middleName;
String lastName;
String jobTitle;
ArrayList<Adress> adresses;
Date birthday;
String department;
Integer mobilePhone;
String email;
String company;
String notes;
    ...

I usually do this using JAXB, but as all the elements are called a and all the attributes n, I don't know how to map this. I really would appreciate a code snippet or any kind of help. Thanks in advance.

Answer 1

You could try doing something like this:

@XmlAccessorType(XmlAccessType.FIELD)
public class ContactAttribute {

    @XmlAttribute(name="n")
    private String attribute;

    @XmlValue
    private String value;

}

@XmlRootElement(name = "cn")
@XmlAccessorType(XmlAccessType.FIELD)
public class Contact {

    @XmlAttribute
    Integer id;

    @XmlAttribute
    Integer rev;

    //...

    @XmlElements(@XmlElement(name = "a"))
    List<ContactAttribute> attributes;
    //...

}

Answer 2

使用Castor映射 ，它将帮助您编组和解组数据。