从bash脚本克隆Git

Question

I am trying to automate my interactions with Git building a script and I am having the following problem.

This works from the command line:

git clone git@github.xxxx.com:blablabla/reponame.git /Users/myname/dev/myfolder

And now I would like to do the same, but from my script. I have the following:

#/bin/bash

repository="git@github.xxxx.com:blablabla/reponame.git"

localFolder="/Users/myname/dev/myfolder"

git clone $repository" "$localFolder

that gives me this error

GitHub SSH access is temporarily unavailable (0x09). fatal: The remote end hung up unexpectedly

Any light on this will be much appreciated

Answer 1

You mean git clone "$repository" "$localFolder" , I'd hope?

Running git clone $repository" "$localFolder is something quite different:

• Because neither variable is within double quotes, their contents are string-split and glob-expanded; thus, if they contained whitespace (generally, characters within $IFS ), they could become multiple arguments, and if they contained globs ( * , [...] , etc), those arguments could be replaced with filenames (or simply removed from the generated argument list, if the nullglob shell option is enabled)
• Because the space between the two arguments is quoted, they are combined into a single argument before being passed to git .

So, for the values you gave, what this script runs would be:

git clone "git@github.xxxx.com:blablabla/reponame.git /Users/myname/dev/myfolder"

...which is quite different from

git clone git@github.xxxx.com:blablabla/reponame.git /Users/myname/dev/myfolder

...as it is giving the /Users/myname/dev/myfolder path as part of the URL.