在F＃中，案例标识符的“是X”运算符吗？

Question

Let's say I have the following discriminated union and value:

type DisUnion = 
    | One of string
    | Two of string
    | Three of string * string

let myVal = One("One")

I know I can use pattern matching to determine which case myVal belongs to, like this:

let whatever (x : DisUnion) = match x with
    | One(str) -> "It was One"
    | Two(str) - > "It was two"
    | Three(str, str) -> "It was three"

But I can't seem to find an operator or method that allows me to determine the case identifier without pattern matching, like:

let isOne (x : DisUnion) = x :? One //I thought this would work, but it doesn't.

How would I do this? Any help is appreciated.

Answer 1

let isOne = function One(_) -> true | _ -> false

请注意，这等效于：

let isOne x = match x with One(_) -> true | _ -> false

Answer 2

There's no such operator built into F#, but there are a couple different approaches to achieving your goal.

A novel approach, which loses type checking and thus wouldn't typically be used, is via reflection. We note that discriminant unions are implement by the F# compiler using, in your example, DisUnion as a base class and each of the union cases, One , Tow , and Three as subclasses of DisUnion . Thus we can implement the following operator:

let (=?) duInstance caseName = 
    let duInstanceTy = duInstance.GetType()
    duInstanceTy.Name = caseName

and use it like so:

> One("hi") =? "One";;
val it : bool = true
> One("hi") =? "Two";;
val it : bool = false
> One("hi") =? "NotValid";;
val it : bool = false

More typical, however, would be to implement a set of static members on DisUnion to do the job in a statically type-checked way. It's a bit verbose to implement, but it's a one time cost since using the static members is nice.

type DisUnion = 
    | One of string
    | Two of string
    | Three of string * string
    static member isOne x =
        match x with
        | One _ -> true
        | _ -> false
    static member isTwo x =
        match x with
        | Two _ -> true
        | _ -> false
    static member isThree x =
        match x with
        | Three _ -> true
        | _ -> false

and use it like so:

> DisUnion.isOne (One("hi"));;
val it : bool = true
> DisUnion.isOne (Two("hi"));;
val it : bool = false
> DisUnion.isOne (NotValid("hi"));;

  DisUnion.isOne (NotValid("hi"));;
  ----------------^^^^^^^^

C:\stdin(5,17): error FS0039: The value or constructor 'NotValid' is not defined