[英]Java regex to find two upper case letters, followed by one space and seven digits
I want to find a regex for the following pattern: "AA XXXXXXX"
(two characters, one space and 7 digits). 我想为以下模式找到一个正则表达式: "AA XXXXXXX"
(两个字符,一个空格和7位数字)。
Example: "AA 1234567"
. 例如: "AA 1234567"
。
Now I can't find the answer. 现在我找不到答案了。
The pattern you want is: 您想要的模式是:
[a-zA-Z]{2} [0-9]{7}
exactly two chars (upper or lower case) followed by space followed by exactly 7 digits. 正好两个字符(大写或小写),后跟空格,后跟正好7位数字。
If the characters can only be uppercase like in the sample string: 如果字符只能像示例字符串中那样是大写字母:
[A-Z]{2} [0-9]{7}
In Java: 在Java中:
Pattern p = Pattern.compile("[A-Z]{2} [0-9]{7}");
Matcher m = p.matcher("AA 1234567");
boolean b = m.matches();
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