如何在LINUX的另一个目录中有选择地创建指向特定文件的符号链接？

Question

I'm not exactly sure how to go about doing this, but I need to create symbolic links for certain files in one directory and place the symbolic links in another directory.

For instance, I want to link all files with the word "foo" in its name in the current directory bar1 that does not have the extension ".cc" and place the symbolic links in a directory bar2.

I was wondering if there was single line command that could accomplish this in LINUX bash.

Answer 1

假设您位于包含目录bar1和bar2目录中：

find bar1 -name '*foo*' -not -type d -not -name '*.cc' -exec ln -s $PWD/'{}' bar2/ \;

Answer 2

Try this:

cd bar1
find . -maxdepth 1 -name '*foo*' -not -name '*.cc'  -exec echo ln -s $PWD/{} ../bar2 \;

Once you are satisfied with the dry run, remove echo from the command and run it for real.

Answer 3

This is easily handled with extended globbing:

shopt -s extglob
cd bar2
ln -s ../bar1/foo!(*.cc) .

If you really want it all on one line, just use the command separator:

shopt -s extglob; cd bar2; ln -s ../bar1/foo!(*.cc) .

The two examples are identical, but the first is much easier to read.

Answer 4

从技术上讲，这不算单行答案...但是可以将其粘贴到单个实例中，并且应该执行您想要的操作。

list=`ls | grep foo | grep -v .cc`;for file in $list;do ln $file /bar2/;done