[英]download a file using apache http
I was trying to download a zip file from a page which requries username/password to access ( html form based authentication). 我试图从需要用户名/密码的页面下载一个zip文件以进行访问(基于html表单的身份验证)。 I am using apache http library for it. 我正在使用apache http库。 Earlier I had worked on something very similar, that page required just password to download the file. 早些时候我从事过非常类似的工作,该页面只需要密码即可下载文件。 Here is my code 这是我的代码
DefaultHttpClient httpclient = new DefaultHttpClient();
httpclient.setRedirectStrategy(new DefaultRedirectStrategy() {
public URI lastRedirectedUri;
public boolean isRedirected(HttpRequest request,
HttpResponse response,
HttpContext context) {
boolean isRedirect = false;
try {
isRedirect =
super.isRedirected(request, response,
context);
} catch (org.apache.http.ProtocolException e) {
e.printStackTrace();
}
if (!isRedirect) {
int responseCode =
response.getStatusLine().getStatusCode();
if (responseCode == 301 ||
responseCode == 302) {
System.out.println("the original response code is" + responseCode);
return true;
}
}
return isRedirect;
}
// public URI getLocationURI(HttpResponse response, HttpContext context)
// throws ProtocolException {
//
// lastRedirectedUri = super.getLocationURI(request , response, context);
//
// return lastRedirectedUri;
// }
});
List<NameValuePair> formparams = new ArrayList<NameValuePair>();
// formparams.add(new BasicNameValuePair("password", arg[1]));
formparams.add(new BasicNameValuePair("password", "*****"));
formparams.add(new BasicNameValuePair("email", "****"));
UrlEncodedFormEntity entity1 =
new UrlEncodedFormEntity(formparams, "UTF-8");
HttpPost httppost =
new HttpPost("https://*************************/l/?next=/s/48750/d/");
// new HttpPost(arg[0]);
httppost.setEntity(entity1);
HttpContext localContext = new BasicHttpContext();
CookieStore cookieStore = new BasicCookieStore();
localContext.setAttribute(ClientContextConfigurer.COOKIE_STORE, cookieStore);
HttpResponse response = httpclient.execute(httppost, localContext);
HttpHost target =
(HttpHost)localContext.getAttribute(ExecutionContext.HTTP_TARGET_HOST);
System.out.println("Final target: " + target);
System.out.println(response.getProtocolVersion());
System.out.println(response.getStatusLine().getStatusCode());
System.out.println(response.getStatusLine().getReasonPhrase());
System.out.println(response.getStatusLine().toString());
HttpEntity entity = response.getEntity();
if (entity != null) {
FileOutputStream fos =
new java.io.FileOutputStream("download.zip");
entity.writeTo(fos);
fos.close();
}
if you open the url provided in the code you will find the form has two parameters by the name email and password , and I have supplied them as formparams ( values commented in the code above ). 如果您打开代码中提供的url,您会发现该表单具有两个参数,名称分别为email和password,我已将它们作为formparams提供(上面代码中注释的值)。 Any help will be greatly appreciated. 任何帮助将不胜感激。
Try using BasicAuthentication. 尝试使用BasicAuthentication。
http://hc.apache.org/httpclient-3.x/authentication.html#Authentication_Schemes http://hc.apache.org/httpclient-3.x/authentication.html#Examples http://hc.apache.org/httpclient-3.x/authentication.html#Authentication_Schemes http://hc.apache.org/httpclient-3.x/authentication.html#Examples
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