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在Lua中实现OOP时尝试调用方法'print'(nil值)

[英]attempt to call method 'print' (a nil value) when implementation OOP in Lua

So, I'm trying to write a simple class in Lua for representing CSV fields: 因此,我试图在Lua中编写一个简单的类来表示CSV字段:

csv_entry = {}
csv_entry.__index = csv_entry

function csv_entry.create(...)
   return arg
end

function csv_entry:tostring()
   local str = string.char()
   for i,v in ipairs(self) do
      if i < #self then
     str = str .. v
      else
     str = str .. v .. ", "
      end
   end
end

function csv_entry:print()
   print(self:tostring())
end

But when I try to use this class like this: 但是当我尝试像这样使用此类时:

c = csv_entry.create("Volvo", 10000, "Eric")
c:print() -- line 25

I get the error message 我收到错误消息

lua: csv.lua:25: attempt to call method 'print' (a nil value)

And I can't really figure out the issue here. 而且我真的无法在这里找出问题。 What am I doing wrong? 我究竟做错了什么?

You probably meant to do is this: 您可能打算这样做:

function csv_entry.create(...)
   return setmetatable(arg, csv_entry)
end

Your posted version of cvs_entry.create just returns it's arguments packed into a table, so this code: 您发布的cvs_entry.create版本仅返回打包在表中的参数,因此此代码:

c = csv_entry.create("Volvo", 10000, "Eric")
c:print()

Is exactly equivalent to this code: 完全等同于以下代码:

c = {"Volvo", 10000, "Eric"}
c:print()

c doesn't contain a print entry, so c.print returns nil and c:print() fails because you're trying to "call" nil . c不包含print条目,因此c.print返回nilc:print()失败,因为您试图“调用” nil


Side note: the implicit arg parameter to variadic functions was removed in Lua 5.1 (6 years ago). 旁注:Lua 5.1(6年前)中删除了可变参数函数的隐式arg参数。 The correct way to do this now is: 现在执行此操作的正确方法是:

function csv_entry.create(...)
    local arg = {...}
    return setmetatable(arg, csv_entry)
end

Or simply: 或者简单地:

function csv_entry.create(...)
   return setmetatable({...}, csv_entry)
end

As long as we're here: you're going to get no output from csv_entry:tostring because it doesn't return anything. 只要我们在这里,您就不会从csv_entry:tostring获得任何输出,因为它不会返回任何内容。 Also, if all you're trying to do is to concatenate a bunch of items with comma separators, you can use table.concat : 另外,如果您要做的就是用逗号分隔符连接一堆项目,则可以使用table.concat

function csv_entry:tostring()
    return table.concat(self, ', ')
end

I rewrite your code to meet what it is for, it runs OK for me: 我重写您的代码以满足其用途,它对我来说运行正常:

csv_entry = {}  

function csv_entry:create(...)
    o = {content = {}}
    self.__index = self;
    setmetatable(o, self)
        for i = 1, arg.n do
            o.content[i] = arg[i];
        end
    return o;
end

function csv_entry:tostring()
    local resStr = ""
    for i, v in pairs(self.content) do
      resStr = resStr .. v;
      if i < #(self.content) then
          resStr = resStr .. ", "
      end
    end
    return resStr;
end

function csv_entry:print()
    print(self:tostring())
end

c = csv_entry:create("Volvo", 10000, "Eric")
c:print()

Like @Mud said, the create(...) in your code is just a regular call and returns all arguments from ..., if you want csv_entry works like a class, then you have to put codes which set metatable and __index into create(...), and return an instance from csv_entry class 就像@Mud所说的那样,代码中的create(...)只是一个常规调用,它从...返回所有参数,如果要使csv_entry像一个类一样工作,则必须将设置metatable和__index的代码放入create(...),然后从csv_entry类返回一个实例

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