[英]in_array function in php always returns false
I have an array like this. 我有这样的数组。
$flds = array("fn", "ln", "em");
I have another associative array like this. 我有另一个这样的关联数组。 this is dynamically returned from JSON POST. 这是从JSON POST动态返回的。
$ret = array("fn" => "xyz", "ln" => "abc", "em" => "s.2", "another" => "123")
I want to search if the first array is existing in the 2nd array. 我想搜索第二个数组中是否存在第一个数组。 I did this: 我这样做:
if ( in_array( $flds, array_keys($ret)))
echo "exists";
else
echo "does not";
It always returns "does not". 它总是返回“不”。 When I print, $flds and array_keys($ret), both look exactly same. 当我打印$ flds和array_keys($ ret)时,它们看起来完全一样。
Anything wrong here? 这里有什么问题吗?
That code is looking for the entire $flds array to be a value in $ret; 该代码正在寻找整个$ flds数组作为$ ret中的值;
You'll probably want to use array_intersect() and then check the length of the result. 您可能需要使用array_intersect() ,然后检查结果的长度。
in_array()
function searches whether the element is an element of the array. in_array()
函数搜索该元素是否为数组的元素。 In your case, you want to determine whether the first array is a subset of keys in the second array. 在您的情况下,您想确定第一个数组是否是第二个数组中键的子集。 Let me show you what works and what does not work: 让我向您展示哪些有效,哪些无效:
/* check if 'fn' is an array key key of $ret */
in_array('fn', array_keys($ret)) // true
/* check if array('fn') is an element of array(array('fn'), 'en') */
in_array(array('fn'), array(array('fn'), 'en')) // true
/* check if $flds is a key of $ret */
in_array( $flds, array_keys($ret)) // false
/* check if all elements of $flds are also keys of $ret */
array() === array_diff($flds, array_keys($ret)) // true
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