可以在不等待进程完成的情况下调用 subprocess.call 吗？

Question

I'm currently using subprocess.call() to invoke another program, but it blocks the executing thread until that program finishes. Is there a way to simply launch that program without waiting for return?

Answer 1

Use subprocess.Popen instead of subprocess.call :

process = subprocess.Popen(['foo', '-b', 'bar'])

subprocess.call is a wrapper around subprocess.Popen that calls communicate to wait for the process to terminate. See also What is the difference between subprocess.popen and subprocess.run .

Answer 2

答案不应该是使用“close_fds”标志吗？

subprocess.Popen(cmd, stdout=None, stderr=None, stdin=None, close_fds=True)