找到文件列表，创建一个目录并在linux中复制这些文件

Question

For example, I want to copy the "file-to-be-copied.txt" from different directories

/home/user1/file-to-be-copied.txt
/home/user2/file-to-be-copied.txt
/home/user3/file-to-be-copied.txt

Then create a new directory based on the user account

/home/user4/user1/
/home/user4/user2/
/home/user4/user3/

Then copy the "file-to-be-copied.txt" to the new created directories

/home/user4/user1/file-to-be-copied.txt
/home/user4/user2/file-to-be-copied.txt
/home/user4/user3/file-to-be-copied.txt

All I know is that it should be done using bash scripting but I don't know how. This is as far as I go

find /home . "file-to-be-copied.txt" | xargs -i mkdir ... cp {} ...

Answer 1

No find necessary, and more so: no xargs (which is almost always superfluous with find, since find has -exec).

cd /home
cp --parents user?/file-to-be-copied.txt user4

Answer 2

for f in $(/usr/bin/find '/home' -name 'file-to-be-copied.txt'); do
  tmpname=${f%/*}
  dirname=${tmpname##*/}
  /bin/mkdir -p $dirname && /bin/cp -p $f $dirname
done

Answer 3

This is the code I used.

    for f in $(find '/home' -name 'file-to-be-copied.txt')
      do
        tmpname=${f%/*}
        dirname=${tmpname##*/}
        mkdir -p /home/user4/$dirname && /bin/cp -p $f /home/user4/$dirname

        echo $f copied to /home/user4/$dirname
      done